insert php code into mysql

[FrEaKmAn]

Hi

I would like to add php code into mysql database. I found one tutorial but I can't get it to work. This is the code

<?php
include 'config.php';

$result = mysql_query("SELECT * FROM test");
list($text) = mysql_fetch_array($result);


/*$text = '<?php include "1.php"; ?>';*/

eval('?>'.$text.'<?php');

?>

and mysql data

CREATE TABLE `test` (
`text` longtext
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `test` (`text`) VALUES ('<?php include \\"1.php\\"; ?>');

and I get this error


Warning: Unexpected character in input: '\' (ASCII=92) state=1 in ...index.php(10) : eval()'d code on line 1

Parse error: parse error, unexpected $end in ...index.php(10) : eval()'d code on line 1

[degsy]

What tutorial are you following?

[FrEaKmAn]

http://www.zimmertech.com/tutorials/php/51/evaluate-php-code-from-mysql.php

[degsy]

Are you manually inserting those backslashes? Remove them. They are causing the error.
If not then check what your php.ini settings to see if you have magic quotes enabled.

[FrEaKmAn]

thanks, for all others, I changed

; Use Sybase-style magic quotes (escape ' with '' instead of \').
magic_quotes_sybase = On

[FrEaKmAn]

Well now when I want to inlcude this into my script I get error again.


Warning: include(news.php?include) [function.include]: failed to open stream: Invalid argument in ...index.php(12) : eval()'d code on line 1

Warning: include() [function.include]: Failed opening 'news.php?include' for inclusion (include_path='.;C:\php5\pear') in ...index.php(12) : eval()'d code on line 1


</b>What I want to do is to make header, leftside, rightside and footer on every page and on one include news. I made script with


if(isset($include)){ ... get data out ...}

and now I want to include news.php?include

[FrEaKmAn]

Well I replaced news.php?include and I made simple news_include.php and it works..