php image

[FrEaKmAn]

HI

I would help so that I can put link to one image in one php file and than set source, like <img src="image.php"> and image will show up. I was trying with simple echo but it doesn't work when I source it...

[degsy]

What code are you using to create the image?

You need to use PHP to create or output an image either by the inbuilt image functions or the header content type.

[FrEaKmAn]

what I want to do is that somebody hosts image on some free hosting sites and then he can create short link for image, like http://www.cybertechhelp.com/images/...ation/boat.gif and he/she enters into form and get out short link for image, something like image.php?boat. And now for avatar we can set link to image or in html <img src="image.php?boat"> and we get boat.gif image

[degsy]

There are different ways to do it.

Here is a basic example where you take the querystring variable name and add the file extension and echo the image

http://domain.com/index.php?imagename

PHP Code:

<?php
if($_GET != ""){
 foreach($_GET as $key => $value){
  echo $key . '<br>';
 }
 
 $filename = 'images/' . $key . '.gif';
 if (file_exists($filename)) {
    echo '<img src="' . $filename . '" alt="' . $filename . '" />';
 } else {
    echo "The file $filename does not exist";
 }
}
?>

and here is an example to output a image using the header function

e.g.

<img src="http://domain.com/index.php?imagename" alt="myimage">

PHP Code:

<?php
Header("Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0");
Header("Expires: Thu, 19 Nov 1981 08:52:00 GMT");
Header("Pragma: no-cache");
Header("Content-Type: image/gif");
foreach($_GET as $key => $value){
$f = 'images/' . $key . '.gif';
}
 
if(!readfile($f)) // Read the image
readfile("images/error.gif"); // If the script can't find the directory, display this image
?>

[FrEaKmAn]

the second option will work but is there anyway to also support other image formats? jpeg and png?

[degsy]

You could reference the exension in the url rather than hardcode it.

The other way would be to use string functions to find a match for the filename and then use the mime_content_type function to get the file type. You could do this using a select case
http://uk2.php.net/manual/en/functio...ntent-type.php

[FrEaKmAn]

hm well if I'm running this on my home server it works with images located on pc. If I put it on server it says that can't show image because of mistakes.

http://url.si/test/image.php?http://...tons_cth/reply

[degsy]

You can't use readfile to open remote files. It for local files only. You may have luck with one of the other file opening fuctions such as fopen.

[FrEaKmAn]

is it possible for little more help. With fopen I can't open even local files

[degsy]

Here is an example for loading remote jpeg images
http://phparadise.de/php-code/image-...offsite-image/

[FrEaKmAn]

can't make it to work...

[degsy]

Maybe your PHP install does not have the required modules to do it.

[degsy]

Here is another example

http://domain.com/index.php?http://images.cybertechhelp.com/i/ban2.gif

PHP Code:

<?
// Set the URL you want to connect to
//$url = "http://www.google.co.uk/intl/en_uk/images/logo.gif";
/*
if(isset($_GET['image'])){
 $url = $_GET['image'];
}
*/
if(!$_SERVER['QUERY_STRING'] == ""){
 $url = $_SERVER['QUERY_STRING'];
}
// Check to see if the file exists by trying to open it for read only
if (!@fopen($url, "r")) {
 $url = "error.gif";
}
 $ext = strtolower(substr($url,-4));
 
 switch($ext){
  case ".gif";
   $type = "image/gif";
   break;
  case ".jpg";
   $type = "image/jpeg";
   break;
  case ".png";
   $type = "image/png";
   break;
  }
 
 
header("Content-Type: $type"); 
$handle = readfile($url);
?>

[oracle128]

Originally Posted by degsy

PHP Code:

$ext = strtolower(substr($url,-4)); 


Might want to tokenize that instead degsy, to handle extensions that aren't 3 characters long (eg. ".jpeg"):

PHP Code:

$tokens = explode(".",$url);
$ext = strtolower(count($tokens)-1); 


Will need to change the switch/case and drop the ".", or keep it and just insert one before $ext.

[degsy]

for this simple script it doesn't really need it.

e.g.

PHP Code:

case ".jpg";
  case "jpeg";
   $type = "image/jpeg";
   break; 


if you did want to do it by the finding the extensions on it's own then you can bypass the explode

PHP Code:

strtolower(substr(strrchr($url,"."),1));